Question

the magnitude of given vector with end point (4,-4,0)and (-2,-2,0) must be

Answer 1

Hey,
Thanks for asking this question.

Let the end points be (x1,y1,z1) and (x2,y2,z2)
where,
(x1,y1,z1) = (4,-4,0)
&
(x2,y2,z2) = (-2,-2,0)

We know that magnitude of a vector with the end points (x1,y1,z1) & (x2,y2,z2) is,

M = √ {(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2}

=> M = √ {(-2-4)^2 + (-2-(-4))^2 + (0-0)^2}

=> M = √ (36+4+0)

=> M = √40

=> M = 2√10

●Magnitude of a vector whose end points are (-4,-4,0) & (-2,-2,0) is, 2√10.

■■■Hope my answer helped.

Answer 2

Answer:

the answer for your question is as follows:

The magnitude of a vector is represented by whole root of the square of the differences of the co-ordinates of x,y and z planes. A vector with end points (4, -4, 0) and (-2, -2, 0) can be represented by

v = (4-(-2))i + (-4-(-2))j + (0–0)k

i.e 6 i - 2j + 0 k

Now, its magnitude is

|v|= √(6)² + (-2)² +0²

= √40

= 2 √10

Hope it helps!