the magnitude of gravitational potential energy of three particles each of mass 6 mg placed of vertices of an equilateral triangle of edge length 1m is.
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Answer:
Potential energy of system with three particles at distance d=dGM2+dGM2+dGM2
=d3GM2
Potential energy of system with three particles at distance 2d=2d3GM2
Thus work done=Change in potential energy=2d3GM2
Explanation:
nelem:
options are: (1)7.8×10-¹⁵ J (2)7.2×10-²¹ J (3)4.96×10-⁴ J (4) 8.1×10-¹³ J
the option one is correct bro...
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...for answer see... the figure
... provided in the picture...
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ans will be exponent of 10^-21
see properly 6 is already divided by 1000 so before commenting be sure either you are right or not.
see properly 6 is already divided by 1000 so before commenting be sure either you are right or not.
Ankit ur steps are right but calculations are wrong u converted milligrams into gram by dividing by 1000 but u should convert it into kilograms ....
the correct ans us opt b=7.2 x 10^-21 J
Oho ha bro I apologize to that.. thanks for correction ...
...
don't apologise we r human!!!!
and we all do mistakes
So nice of you.
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