Question

the magnitude of image distance of a bus as seen by the driver of an ambulance in rear view mirror of focal length 10cm is about (assume bus is situated 10meter from the rear view mirror)
a) 0.4 m
b) 0.2 m
c) 0.3 m
d) 0.1 m

Answer 1

Answer:

0.1m

Explanation:

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Answer 2

Given:

• Object distance = 10 metres
• Focal length of mirror = 10 cm

To find:

• Image distance ?

Calculation:

The general equation of Mirror Formula is:

$\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

• Putting all values in 'cm' unit :

$\implies \dfrac{1}{( + 10)} = \dfrac{1}{v} + \dfrac{1}{( - 1000)}$

$\implies \dfrac{1}{ 10} = \dfrac{1}{v} - \dfrac{1}{1000}$

$\implies \dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{1000}$

$\implies \dfrac{1}{v} = \dfrac{100 - 1}{1000}$

$\implies \dfrac{1}{v} = \dfrac{99}{1000}$

$\implies v = \dfrac{1000}{99}$

$\implies v = 10.1 \: cm$

$\implies v \approx 0.1 \: m$

So, image distance is approximately 0.1 metres.