Physics, asked by ashishpatel24631, 11 months ago

The magnitude of linear momentum of a particle moving at a relativistic speed v is proportional to
(a) v
(b) 1 − v2/c2
(c) √1-v2/c2
(d) none of these

Answers

Answered by nishaupneja5
1

Answer:

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Explanation:

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Answered by bhuvna789456
1

The magnitude of linear momentum of a particle moving at a relativistic speed v is proportional to None of the option .

Explanation:

A particle moving with a relativistic speed v has the linear momentum and it is shown as  

p = \mathrm{mov}_{1}-\mathrm{v} 2 \mathrm{c} 2

Here, mov 1 is the particle’s rest mass.

So, the linear momentum is proportionate to v 1-v 2 c 2.

So, it is proven that none of the options like (a) V, (b) 1-v 2 / c 2and (c) \sqrt{1}-v 2 / c 2 provided above is correct.

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