Question

The magnitude of magnetic field for to current carrying arc of radius R having a current I substanding an angle 60° at the centre O is

Answer 1

magnitude of magnetic field in case of circular arc is given by $B=\frac{\mu_0i}{4\pi r}[\theta]$

where $\mu_0$ permeability of medium in vaccum, r is the radius of circular arc , i is the current carrying by circular arc and $\theta$ is the angle subtending at the centre .

so, magnetic field , B = $\frac{\mu_0I}{4\pi R}\frac{\pi}{3}$
= $\frac{\mu_0I}{12R}$

Answer 2

Answer:

hope this helps you to know