Question

The magnitude of magnetic field produced by the current carrying

straight wire of length L carrying a current i, at point P is ​

Answer 1

Answer:

Magnetic Field Produced by a Current-Carrying Circular Loop

B=μ0I2R(at center of loop) B = μ 0 I 2 R ( at center of loop ) , where R is the radius of the loop. This equation is very similar to that for a straight wire, but it is valid only at the center of a circular loop of wire.

The magnetic field due to a finite length wire

B=

4π

μ

0

.

r

i

(sinϕ

1

+sinϕ

2

)

Here, ϕ

1

=0

o

and ϕ

2

=45

o

∴B=

4π

μ

0

r

i

(sin0

o

+sin45

o

)

=

4π

μ

0

r

i

2

1

=

8πl

2

μ

0

i