Question

The magnitude of Orbital angular momentum of an electron is given by=√5h/π. How many orbitals of this type are possible belonging to an Orbit?​

Answer 1

Answer:

See below.

Explanation:

We are given the orbital angular momentum as,

$L=\dfrac {\sqrt {5}H}{\pi }$

According to the Bohr's model,

$L=n\dfrac {H}{2\pi }$

Where n = 1, 2, 3 or any positive integer values. Hence, the angular momentum is an integral multiple of H/2 pi.

Square Root of 5 is not an integer. Hence, no orbitals will possess an angular momentum as given.

Answer 2

Answer:

It's wrong

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