The magnitude of rectangular components of a vector are equal if its angle with the x-axis is
Answers
Explanation:
The angle between two vectors can be determined from their dot product:
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))theta = arccos(1 / (1 * SQRT(2))
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))theta = arccos(1 / (1 * SQRT(2))theta = pi / 4 radians = 45 degrees
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))theta = arccos(1 / (1 * SQRT(2))theta = pi / 4 radians = 45 degreesIn three dimensions, the result is
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))theta = arccos(1 / (1 * SQRT(2))theta = pi / 4 radians = 45 degreesIn three dimensions, the result istheta = arccos(1 / SQRT(3)), which is approximately 0.955 radians or 54.7 degrees.
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))theta = arccos(1 / (1 * SQRT(2))theta = pi / 4 radians = 45 degreesIn three dimensions, the result istheta = arccos(1 / SQRT(3)), which is approximately 0.955 radians or 54.7 degrees.In n dimensions, the result is
The angle between two vectors can be determined from their dot product:cos(theta) = (vector_1 dot vector_2) / (||vector_1||*||vector_2||)theta = arccos((vector_1 dot vector_2) / (||vector_1||*||vector_2||))A vector lying along the x-axis is 1 x-hat.In two dimensions, a vector parallel to one with equal rectangular components is 1 x-hat + 1 y-hat.theta = arccos(((1 x-hat) dot (1 x-hat + 1 y-hat)) / (||1 x-hat||*||1 x-hat + 1 y-hat||))theta = arccos(1 / (1 * SQRT(2))theta = pi / 4 radians = 45 degreesIn three dimensions, the result istheta = arccos(1 / SQRT(3)), which is approximately 0.955 radians or 54.7 degrees.In n dimensions, the result istheta = arccos(1 / SQRT(n))