Question

The magnitude of relative velocity of two cars A and Bis 10 m/s. If the velocity of car A is 30 m/s then velocity with which car B is moving may be (Assume both cars are moving in same direction) 40 m/s 30 m/s 25 m/s 35 m/s​

Answer 1

Explanation:

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Relative velocity:

define as a velocity of individual with respect to observer.

It depends on the frame of reference of observer.

$\implies\bf V_B - V_A = V{relative}$

$\implies\rm V_B = V{relative} + V_A$

$\implies\rm V_B = 10 + 30 = 40\: ms^{-1}$

★So velocity of B will be 40 m/s.

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Answer 2

Given: The magnitude of the relative velocity of two cars A and B is 10 m/s and the velocity of car A is 30 m/s.

To find: The velocity with which car B is moving.

Solution:

• The velocity of a car is the displacement of the car in unit interval of time.

• Let the velocities of car A and car B be $v_{A}$ and $v_{B}$, respectively.

• If two cars A and B are moving in a straight line with velocities $v_{A}$ and $v_{B}$ respectively, the relative velocity of car A with respect to car B is calculated as,

        $v_{AB} = v_{B} - v_{A}$

        $10 ms^{-1} = v_{B} - 30ms^{-1}$

• On rearranging, the value of $v_{B}$ is found to be equal to,

        $v_{B} = 40ms^{-1}$

Therefore, the velocity with which car B is moving is 40ms⁻¹.