The magnitude of the average electric field normally present in earth's
atmosphere just above the surface of earth is about 300 N/C directed
downwards (radially inwards towards the centre of earth). The total net
surface charge carried by Earth is nearly .........
(Assume the earth to be conductor)
(E. = 8.85 10-12MKS, radius of earth = 6400km)
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Answer:
Given
a
2
=13 and a
5
=25
We know that
a
n
=a+(n−1)d
∴a
2
=a+(2−1)d
⇒13=a+(2−1)d
⇒a+d=13 ...(i)
and a
5
=a+(5−1)d
⇒25=a+4d
⇒a+4d=25 ...(ii)
Now, subtracting (i) from (ii), we get
3d=12
⇒d=4
Now a+d=13 [from (i)]
⇒a=9
Hence, a
7
=a+6d=9+6(4)
⇒a
7
=33
Explanation:
It is not necessary that the degree of the sum of two polynomials each of degree 5 is always 5.
Let p(x)=−x
5
+x
2
+2 and q(x)=x
5
+x
3
+4
p(x) and q(x) each are of degree 5.
But p(x)+q(x) =−x
5
+x
2
+2+x
5
+x
3
+4=x
3
+x
2
+6 which is not of degree 5.
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