Physics, asked by ajaykumarshukla1211, 1 year ago

The magnitude of the earth’s magnetic field at a place is B₀ and the angle of dip is δ . A horizontal conductor of length l lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is
(a) Zero(b) B₀l v sinδ(c) B₀l v(d) B₀l v cosδ

Answers

Answered by prmkulk1978
14

   Correct Answer is B:  B₀l v sinδ

Explanation :

  When a conductor is  lying along the magnetic north-south, it moves eastwards  and it will cut vertical component of B₀.

Formula :

So induced emf   e=vBVl

=v(B₀sinδl)

=B₀lvsinδ

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