The magnitude of the earth’s magnetic field at a place is B₀ and the angle of dip is δ . A horizontal conductor of length l lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is
(a) Zero(b) B₀l v sinδ(c) B₀l v(d) B₀l v cosδ
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Correct Answer is B: B₀l v sinδ
Explanation :
When a conductor is lying along the magnetic north-south, it moves eastwards and it will cut vertical component of B₀.
Formula :
So induced emf e=vBVl
=v(B₀sinδl)
=B₀lvsinδ
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