Physics, asked by sibibala18, 16 days ago

The magnitude of the electric field of an electromagnetic
wave increases from 315 to 945 N/C. Determine the
wave intensities for the two values of the electric field.

Answers

Answered by tinaparrpublicc

0

Explanation:

E= 315N/C

E= 945N/C

s= ce0E2

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