Physics, asked by viswa3507, 9 months ago

The magnitude of the electrostatic force between two charges +4C and -3C kept at a distance 1m apart is ? Answer the question with proper steps.​

Answers

Answered by zahaansajid
4

F = kq1q2/

k = 9 × 10^9

q1 = +4C

q2 = -3C

r = 1m

force =  \frac{kq1q2}{ {r}^{2} }  \\   \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \: \:  =  \frac{9 \times  {10}^{9}  \times 4 \times 3}{ {1}^{2} }  = 108 \times  {10}^{9} \\  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \: \:  = 1.08 \times  {10}^{11} newton

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