the magnitude of the vector product of two vectors is sqrt 3 times their scalar product. what is the angle between the two vectors
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why you took 8? and why you took Tan?
Answered by
25
Magnitude of:
vector product=ABsin(x)
scalar product=ABcos(x)
Given...
AB cos(x) = (sqrt3)AB sin(x)
=>cos(x)/sin(x) =(sqrt3)
=>cot(x)=(sqrt3)
=>x=30°
so 30° is your answer...
Hope it helps...
Regards,
Leukonov/Olegion.
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