Question

the magnitude of two charges is doubled and the distance of their separation is also doubled the electrostatic force between them will ​

Answer 1

Answer:

stays the same

Explanation:

answer is shown in the clip

Answer 2

Answer:

The magnitude of two charges is doubled and the distance of their separation is also doubled the electrostatic force between them will ​be the same

Explanation:

• The force acting between stationary charges is called electrostatic force

• The coulomb's law gives the magnitude of the force as

        $F=\frac{Kq_{1} q_{2} }{r^{2} }$

        where  $K=9*10^{9}$

        $q_{1} , q_{2}$ - the charges

        $r$- the distance between the charges

From the question, we have given that

the charges are doubled, that is $q'=2q$

and the distance between them is also doubled

$r'=2r$

the new force is $F_{new} =\frac{Kq'_{1} q'_{2} }{r'^{2} }=\frac{K*2q_{1}* 2q_{2} }{4r^{2} }=F$