the magnitude of two forces 4N and 3N acts on a body of mass m the resultant of these two forces is 5N angle between them is
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As the two force quantities are vevtors, so we will add them through vector law of addition.
Resultant vector= under root a^2 +b^2 +2abcostheta
Since the angle between them is 90 (cos90=0)
Resultant vector = under root a^2 +b^2
a=3N. b=4N
Resultant vector = 5N (magnitude)
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5^2=4^2+3^2+2*3*4cos(theta)
25=16+9+24cos(theta)
cos(theta)=o
theta=pi/2
angle between them=pi/2
25=16+9+24cos(theta)
cos(theta)=o
theta=pi/2
angle between them=pi/2
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