Question

The magnitude of two mutually perpendicular vectors a and b are 6 and 8 units respectively find out the Magnitude of A-B?

Answer 1

Answer:

A+(-b)=

${a}^{2} + {b}^{2} - 2ab \times \cos( \alpha ) = 36 + 64 - 96 \times \cos(90) = 100 - 0 = 100 \\ mod( a - b) = \sqrt{100} = 10 \\ the \: answer \: is \: 10$