Question

The magnitude of two vector A and B are 5 and 4 unit respectively and the angle between them is 30°. Find the value A.B

Answer 1

$\textbf{Answer :}$

Given that,

|A| = 5, |B| = 4 and the angle between them is θ = 30°

Now, A. B

= |A| |B| sinθ

= (5) (4) (sin30°)

= 20 sin30°

= 20 × √3/2

= 10√3

#$\textbf{MarkAsBrainliest}$

Answer 2

magnitude if A = 5
magnitude of B= 4
(A,B)= 30
A.B= lAl .lBl.cos(A,B)
= 5*4* cos30
= 20*√3/2
=10√ 3 units
hope this helps u dear