Physics, asked by monishaganapathy118, 5 hours ago

The magnitude of two vectors are 3 and 4 units and their product is 6 units. the angle between the vectors is

π/6
π/3
π/2​

Answers

Answered by NewGeneEinstein
5

Answer:-

A=3

B=4

\sf \overrightarrow{A}.\overrightarrow{B}=6

We know that

\boxed{\sf \overrightarrow{A}.\overrightarrow{B}=ABcos\theta}

\\ \rm\longmapsto cos\theta=\dfrac{\overrightarrow{A}.\overrightarrow{B}}{AB}

\\ \rm\longmapsto cos\theta=\dfrac{6}{3\times 4}

\\ \rm\longmapsto cos\theta=\dfrac{6}{12}

\\ \rm\longmapsto cos\theta=\dfrac{1}{2}

\\ \rm\longmapsto cos\theta=cos60

\\ \rm\longmapsto \theta=60°

Converting to radian:-

\\ \rm\longmapsto 60°=\dfrac{\pi}{180}\times 60

\\ \rm\longmapsto 60°=\dfrac{\pi}{3}rad

Hence option b is correct.

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