Question

The magnitude of two vectors are 3 and 4 units and their dot product is 6 units. The angle between the vectors is.

Answer 1

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Let the two vectors be A and B.

According to your question,

|A| = 2m

|B| = 3m

Angle between them is 60°, so θ = 60°

Now,

(a) Scalar (DOT) product:

A.B = |A| |B| cos θ

= 2 x 3 x cos 60°

= 6 x 1/2

= 3

(ii) Vector (CROSS) product:

A x B = |A| |B| sin θ

= 2 x 3 x sin 60°

= 6 x √3/2

= 3√3

Answer 2

            THE ANSWER IS :

      = 6=3×4×cos-theta

                     = 1/2=costumer

                                     =Theta =30