Question

the magnitude of vector -3i+2j+√3k

Answer 1

Answer:

√16 = 4

Explanation:

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Answer 2

Given :

▪ A vector quantity has been provided.

$\bigstar\:\underline{\boxed{\bf{\red{\vec{A}=-3\hat{i}+2\hat{j}+\sqrt{3}\hat{k}}}}}$

To Find :

▪ Magnitude of the given vector quantity.

SoluTion :

If Ax, Ay, Az are the rectangular components of vector A and î, j, k are are the unit vectors along X-, Y- and Z-axis respectively, then

$\dag\bf\:\vec{A}=A_x\hat{i}+A_y\hat{j}+A_z\hat{k}$

Magnitude of vector :

$\dashrightarrow\bf\:A=\sqrt{(A_x)^2+(A_y)^2+(A_z)^2}\\ \\ \dashrightarrow\sf\:A=\sqrt{(-3)^2+(2)^2+(\sqrt{3})^2}\\ \\ \dashrightarrow\sf\:A=\sqrt{9+4+3}\\ \\ \dashrightarrow\sf\:A=\sqrt{16}\\ \\ \dashrightarrow\underline{\boxed{\bf{\green{A=4\:unit}}}}\:\orange{\bigstar}$