Question

the magnitude of vector product of two unit vectors making an angle of 60 degree with each other is​

Answer 1

Answer: see below

Explanation:

Answer 2

Answer:

Below is the detailed answer.

Explanation:

The magnitude of vector product of two unit vectors makes an angle of 60 degrees with each other. We have to find their product:

Naming the vectors Set a and Set b, while applying formula:

Set a=(2,0) and b=(2*cos(60^0),2*sin(60^0)

so , this means to subtract a vector is to add the negative vector where the negative vector has opposite direction but same magnitude.

So B¯−A¯ is the same as B¯+(−A¯)

Placing values:

a-b = (2–2*cos(60^0),0–2*sin(60^0)) = (2–1,-2*sqrt(3)/2) = (1,-sqrt(3))

||a-b|| = sqrt((a-b)^2) = sqrt(1^2+3) = 2

2 is the answer.