The magnitude of vector product of two
unit vectors making an angle of 60q with
each other is
(A) 1 (B) 2
(C) 3/2 (D) 3 2/
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So, the value of the cross product will be 1*1*sin60 which will be equal to √3/2 which is only the value of sin60. Hence the magnitude will be found to be √3/2 in which the two vectors are making an angle of 60 with each other.
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