the magnitude of vector product of two vectors is root 3 times of their scalar product then what is the angle between these two vectors
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Explanation:
We know
|A×B|=|A||B|sinθ
and
|A⋅B|=|A||B|cosθ
We are also given that
|A×B|=3–√|A⋅B|
Subbing the first two equations into the last equation yields
|A||B|sinθ=3–√|A||B|cosθ
Dividing both sides of the equation by |A||B|cosθ gives
tanθ=√ 3
θ=60
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