Question

The magnitude of vector product of two vectors making an angle of 60degree with each other is
1) 1 2) 2 3) 3/2 4) underroot 3/2​

Answer 1

$\huge \text{\mathbb {\underline {ANSWER}}}$

The magnitude of the cross product will be $\frac{\sqrt{3}}{2}$

$\huge \text{\mathbb {\underline {EXPLANATION}}}$

Let, P and Q be two vectors

      angle between them be Ф

Vector product also called as cross product between P and Q is given by

Cross Product = $\vec{P} \times \vec{Q}$

                        = PQsinФ

Given that,

Ф = 60°

sinФ = sin60

        = $\frac{\sqrt{3}}{2}$

Putting this value in we get,

Cross Product = PQ * $\frac{\sqrt{3}}{2}$

Hence,

The correct answer will be option (4) $\frac{\sqrt{3}}{2}$

Answer 2

Answer:

4) $\sqrt{3}$/2

by vector product rule