Physics, asked by harisreeHari7797, 6 months ago

The magnitude of vector , V ⃗ =2 i ∧ +5 j ∧ −6 k ∧ V→=2i∧+5j∧−6k∧ is

Answers

Answered by PharohX
3

Explanation:

magnitude \:  \: of \:  \: vector \:  =  \sqrt{a {}^{2}  +  {b}^{2} +  {c}^{2}  }  \\

Here

v = 2i + 5j -6k

 |v|  =  \sqrt{ {2}^{2}  +  {5}^{2} + (  { - 6}^{2} ) }  \\  \\  =  \sqrt{4 + 25 + 36}  \\  \\  \sqrt{65 }  \:  \: unit

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