the main gate of a building is 2.6 M broad it can be opened by applying a force of 80Newton at the middle of the gate .calculate the least force which can open the gate.where should the force be applied
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a=2.6m
f=80n
m=?
we know
f=ma
f/a=m
80/2.6=m
m=30.76
therefore m=30.76kg
arham34:
if you have not undestood then ask me
no its wrong bro
in my book 40 is the answer
sorry i didn't understood
the answer is 40N
because 80/2=40
the wuestion was so simple i just take it in another way the right answer is that only
least force means left force
question says that force is applied in the middle and we ha ve to calculate the other 2 part so,i have divided it
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