Question

the main gate of a building is 2.6m broad. it can be opened by applying a force 80n at the middle of the gate calculate tbe least force which can open the gate step by step solution​

plese give me answer

give me answer

Answer 1

Answer:

The force applied at the middle of gate = 80 N  

The distance of gate from hinge = 2.6 m  

The distance at which the 80 N of force is applied = 2.6/2 = 1.3 m  

 

The minimum force will be required if the force is applied at the free end of the gate = 2.6 m  

Thus, by principle of moments

 

F1 x d1 = F2 x d2  

 

80 x 1.3 = F2 x 2.6  

 

Thus, F2 = (80 x 1.3)/2.6 = 40 N

Explanation:

Answer 2

the force is applied pn hings