Question

the main gate of building is 2.6 metre broad it can be opened by applying a force of 80 Newton at the middle of gate calculate the least force which can open the gate​

Answer 1

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the gate Can be opened with 40 Newton of force

Answer 2

Answer is 40 N

Force = 80N

Distance = 2.6 m

The distance at which the 80 N of force is

applied = 2.6/2 = 1.3 m

The minimum force will be required if the force is applied at the free end of the gate = 2.6 m

Thus, by principle of moments

F1 x d1 = F2 x d2

80 x 1.3 = F2 x 2.6

Thus, F2 = (80 x 1.3)/2.6

=40 N

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