Question

the man brought two TV set for 42,500 .He sold at a loss of 10%.If the selling price of each TV set is same determine the cost price of each set.​

Answer 1

Answer:

Cost Price of First set = ₹19125

Cost Price of Second set = ₹23375

Step-by-step explanation:

Given : A man bought two TV sets for Rs 42500.He sold one at a loss of 10% and other at a profit of 10%.

To find : If the selling price of each TV set is same determine the cost price of each set?

Solution :

Total cost of 2 TV sets = ₹42500

Let the cost of First TV set be x

Then,

Cost of second TV set = ₹(42500-x)

Selling price of First TV set is

$\red{ \sf{ SP_ 1 = x + 10\% \: of \: x}}$

$\red{ \sf{ \: \: \: SP_ 1 = \frac{110x}{100} }}$

Selling price of second TV set is

$\red{\begin{gathered}SP_2= 42500-x-10\% \text{ of }(42500-x)\\\\SP_2= \frac{90(42500-x)}{100}\end{gathered} }$

S.P of First TV set = S.P of Second TV set

110x/100 = 90(42500 - x)/100

11x = 90(42500−x)

11x = 382500 - 9x

20x = 382500

x = 19125

Therefore, Cost Price of First set = ₹19125

Cost Price of Second set = ₹23375