The man is away from the train. Plz help me
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v0= 0m/s
a= 2m/s^2
x0= 0m
So, x(t)=t^2 (m)
Man:
v0=k
a= 0m/s^2
x0= -9m
So, x(t)=-9+v0t (m)
To find out what is the position of the train when t=10s,
x(10)=10^2=100m
Now, to find out what is the speed of the man when he gets into the train, which is also when t=10s,
100=-9+v0*10
v0=k=10,9m/s
The speed of the man has to be 10,9m/s.
Anonymous:
thanks
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