Question

the man is thrice is old as his son. in 10 years time his age will be double than his sons age find their present ages​

Answer 1

Step-by-step explanation:

present age of son = x

present age of father = 3x

age of son after 10 years = x + 10

age of father after 10 years = 3x + 10

given 3x + 10 = 2(x + 10)

=> 3x + 10 = 2x + 20

=> 3x - 2x = 20 - 10

=> x = 10

therefore son's present age = x => 10 years

father's present age = 3x => 30 years

Answer 2

Answer:

man = 3* son_____(1)

man +10= 2*(son+10)

man+10= 2son +20

man = 2*son +10____(2)

sub (1) in (2)

3*son= 2*son +10

2*son= 10

son = 5

man = 3*son = 3*5= 15

man is 15 and son is 5