Question

The man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son. Find their present ages.

Answer 1

Let the age of the son be x years.

Age of the father will be 2x.

20 years ago, age of the father would have been 2x-20 and that of the son would have been x-20

Therefore, 2x-20 = 12(x-20)

2x - 20 = 12x - 240

12x - 2x = 240 - 20

10x = 220

x = 22

Hence, the present ages of son and father is 22 and 44 respectively.

Answer 2

Step-by-step explanation:

here's the solution

age of son 22

man 44