The management of a hotel has employed 2 managers, 5 cooks and 8 waiters.The monthly salaries of the manager, the cook and the waiter are Rs.3000, Rs.1200 and Rs.1000 respectively. Find the mean salary of the employees.
Answers
Answer:
The mean salary of employees is Rs 1333.33
Step-by-step explanation:
Given:
No of Managers = 2
No of Cooks = 5
No of Waiters = 8
Monthly salary of a manager = Rs . 3000
Monthly salary of a cook = Rs . 1200
Monthly salary of a waiter = Rs . 1000
To find:
Mean salary of employee = ?
Solution:
Mean salary of employee = Total salary / total no of employees
Total No of employees = 2 + 5 + 8
= 7 + 8
= 15
Salary of 2 managers = 2 * 3000
= 6000
Salary of 5 cooks = 5 * 1200
= 6000
Salary of 8 waiters = 8 * 1000
= 8000
Total Salary = 8000 + 6000 + 6000
= Rs 20,000
Mean salary = Total Salary / total employees
= 20,000 / 15
= Rs 1333.333