Math, asked by ciyusingh, 11 months ago

the mark obtained by four examinees are as follow A:B=2:3, B:C=4:5, C:D=7:9, find the continued ratio.
A:B=2:3.​

Answers

Answered by lekhanabheesetty
11

A : B = 2 : 3

B : C = 4 : 5

C : D = 7 : 9

B is common in the first and second ratio :

The LCM of 3 and 4 is :

12

We multiply the first ratio by 4 and the second ratio by 3.

A : B = 8 : 12

B : C = 12 : 15

A : B : C = 8 : 12 : 15

C : D = 7 : 9

The LCM of 7 and 15 is 105

We multiply the ratio of A : B : C by 7 and C : D by 15

A : B : C = 56 : 84 : 105

C : D = 105 : 135

A : B : C : D = 56 : 84 : 105 : 135

Answered by chaildaksh007
0

Answer:

A : B = 2 : 3

B : C = 4 : 5

C : D = 7 : 9

B is common in the first and second ratio :

The LCM of 3 and 4 is :

12

We multiply the first ratio by 4 and the second ratio by 3.

A : B = 8 : 12

B : C = 12 : 15

A : B : C = 8 : 12 : 15

C : D = 7 : 9

The LCM of 7 and 15 is 105

We multiply the ratio of A : B : C by 7 and C : D by 15

A : B : C = 56 : 84 : 105

C : D = 105 : 135

A : B : C : D = 56 : 84 : 105 : 135

Step-by-step explanation:

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