Question

the mark (out of the 100) obtained by a group of students in a science test are 85,76, 90,85,39 ,48,56,95,81and 75 find the,(a) highest and lowest mark obtained by student (b) mean marks obtained (c) number of student securing marks more than the mean marks.

Answer 1

Hola user!!!

a). Highest marks is 95 and
lowest marks is 39.

b).
$mean = \frac{sum \: of \: observations}{total \: observations}$

$= \frac{85 + 76 + 90 + 85 + 39 + 48 + 56 + 95 + 81 + 75}{10}$

$= \frac{730}{10}$

= 73

c). No. of students securing more than the mean marks is 7 that are :-

85, 76, 90, 85, 95, 81, 75

Hope it helps u!!

Answer 2

Hey mate,
(a) We can arrange the series in ascending or descending order.
Ascending: 39,48,56,75,76,81,85,85,90,95.
Highest marks are 95 and lowest marks are 39.

(b) Mean means average. So,average of this series:
(39+48+46+75+76+81+85+85+90+95)/10
=730/10
=73

(c)No. of students securing marks more than mean marks i.e. 73 are:
75,76,81,85,85,90,95
Counting these we get the answer as 7.

Hope it helps
If so, then please mark the brainliest.