Question

the marked price of a water cooler is rs 5,400.The shopkeeper offers an off season discount of 20% on it . Find its selling price .

Answer 1

Solution:-

》given:-

》market price of a water cooler = 5400 rupees

》discount = 20%

》then :-

》20% of 5400

》5400×1/5 = 1080rupees

》selling price = 5400-1080

= (4320rupees) ans

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Answer 2

sp = mrp × (100-- d%)/100
=5400 ×(100-- 20)/100
=5400× 80 /100
=54×80
=4320 rs