Question

The markings of an aluminum ruler and a brass are perfectly aligned at 0 degree Celsius.?
How far apart (in cm) will the 25.0 cm marks be on two rulers at 104.7 degree Celsius, if alignment on the left-hand ends of the rulers is maintained?

Answer 1

Answer:

Difference in the length of two scales is given as

$L_{Al} - L_{brass} = 0.013 cm$

Explanation:

As we know that if temperature of the solid rod is increased then due to thermal expansion its length will increase

Here we know that the coefficient of thermal expansion is given as

$\alpha_{brass} = 19 \times 10^{-6}$

the coefficient of thermal expansion is given as

$\alpha_{Al} = 24 \times 10^{-6}$

Now final length of 25 cm mark for both scale is given as

$L_{Al} = 25(1 + (24 \times 10^{-6})(104.7 - 0))$

$L_{brass} = 25(1 + (19 \times 10^{-6})(104.7 - 0))$

now difference in length is given as

$L_{Al} - L_{brass} = 25(104.7)(24 \times 10^{-6} - 19\times 10^{-6})$

$L_{Al} - L_{brass} = 0.013 cm$

#Learn

Topic : thermal Expansion

https://brainly.in/question/14359342

Answer 2

Answer: 0.013 cm

Explanation:

As we know that if temperature of the solid rod is increased then due to thermal expansion its length will increase

Here we know that the coefficient of thermal expansion is given as

the coefficient of thermal expansion is given as

Now final length of 25 cm mark for both scale is given as

now difference in length is given as 0.013 cm

Hence We Get The Answer