The marks Cout of 100) obtained by a group of students in a Moth test are 84 75, 90, 84,39,48,56, 95, 81 and 75 Find the
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Hey mate,
(a) We can arrange the series in ascending or descending order.
Ascending: 39,48,56,75,76,81,85,85,90,95.
Highest marks are 95 and lowest marks are 39.
(b) Mean means average. So,average of this series:
(39+48+46+75+76+81+85+85+90+95)/10
=730/10
=73
(c)No. of students securing marks more than mean marks i.e. 73 are:
75,76,81,85,85,90,95
Counting these we get the answer as 7.
Hope it helps
If so, then please mark the brainliest.
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