The marks in some post degree examination are Normally distributed mean= 500 and deviation = 100 we have to pass 550 students out of 674 students who are appearing in the examination. what should be the minimum marks for passing the examination
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Answer:
Given,
μ=500 (mean)
σ=100 (standard deviation)
Tom does better than what percentage?
Tom got 585 marks
we will have to find how many students got less than 585
x<585 (find the probability)
converting the problem in standard form
Z=(x−μ)/σ
for x=585
Z=(585−500)/100=0.85
P(Z<0.85)=P(Z<0)+P(0<Z<0.85)
P(Z<0)=0.5
P(0<Z<0.85)=0.3023 (from Z- table)
so the total probability=0.5+0.3023=0.8023
so Tom got more than 80.23% of students
THANK YOU
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