Math, asked by sweetypushpam1997, 9 months ago

The marks obtained by 10 students are 52, 80, 35, 58, 45, 50, 25, 54, 38, 60. See the median size of the scores?

Answers

Answered by sudiptamaji2007
0

Step-by-step explanation:

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10th

Maths

Statistics

Mean of Grouped Data

Find the mean marks of stud...

STATISTICS

Find the mean marks of students from the following cumulative frequency distribution:

Marks Number of students

o and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

November 22, 2019

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Ayan Keshari

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ANSWER

Here we have, the cumulative frequency distribution. So, first we convert it into an ordinary frequency distribution. we observe that are 80 students getting marks greater than or equal to 0 and 77 students have secured 10 and more marks. Therefore, the number of students getting marks between 0 and 10 is 80-77= 3.

Similarly, the number of students getting marks between 10 and 20 is 77-72= 5 and so on. Thus, we obtain the following frequency distribution.

Marks Number of students

0-10 3

10-20 5

20-30 7

30-40 10

40-50 12

50-60 15

60-70 12

70-80 6

80-90 2

90-100 8

Now, we compute mean arithmetic mean by taking 55 as the assumed mean.

Computative of Mean

Marks

(x

i

) Mid-value (f

i

) Frequency u

i

10

x

i

−55

f

i

u

i

0-10 5 3 -5 -15

10-20 15 5 -4 -20

20-30 25 7 -3 -21

30-40 35 10 -2 -20

40-50 45 12 -1 -20

50-60 55 15 0 0

60-70 65 12 1 12

70-80 75 6 2 12

80-90 85 2 3 6

90-100 95 8 4 32

Total

∑f

i

=80 ∑f

i

u

i

= -26

We have,

N= sumf

i

=80,∑f

i

u

i

=−26, A= 55 and h= 10

X

=A+h[

N

1

∑f

i

u

i

]

X

=A+h[

N

1

∑f

i

u

i

]

⇒ =55+10× 80−26 =55−3.25=51.75

Answered by avk6418peh6wh
0

Answer:

51

Step-by-step explanation:

The marks in ascending order

25,35,38,45,50,52,54,58,60,80

Median is middle term

If even avg. of middle numbers

Median=50+52/2=51

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