The marks obtained by 10 students are 52, 80, 35, 58, 45, 50, 25, 54, 38, 60. See the median size of the scores?
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Step-by-step explanation:
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10th
Maths
Statistics
Mean of Grouped Data
Find the mean marks of stud...
STATISTICS
Find the mean marks of students from the following cumulative frequency distribution:
Marks Number of students
o and above 80
10 and above 77
20 and above 72
30 and above 65
40 and above 55
50 and above 43
60 and above 28
70 and above 16
80 and above 10
90 and above 8
100 and above 0
November 22, 2019
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Ayan Keshari
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ANSWER
Here we have, the cumulative frequency distribution. So, first we convert it into an ordinary frequency distribution. we observe that are 80 students getting marks greater than or equal to 0 and 77 students have secured 10 and more marks. Therefore, the number of students getting marks between 0 and 10 is 80-77= 3.
Similarly, the number of students getting marks between 10 and 20 is 77-72= 5 and so on. Thus, we obtain the following frequency distribution.
Marks Number of students
0-10 3
10-20 5
20-30 7
30-40 10
40-50 12
50-60 15
60-70 12
70-80 6
80-90 2
90-100 8
Now, we compute mean arithmetic mean by taking 55 as the assumed mean.
Computative of Mean
Marks
(x
i
) Mid-value (f
i
) Frequency u
i
10
x
i
−55
f
i
u
i
0-10 5 3 -5 -15
10-20 15 5 -4 -20
20-30 25 7 -3 -21
30-40 35 10 -2 -20
40-50 45 12 -1 -20
50-60 55 15 0 0
60-70 65 12 1 12
70-80 75 6 2 12
80-90 85 2 3 6
90-100 95 8 4 32
Total
∑f
i
=80 ∑f
i
u
i
= -26
We have,
N= sumf
i
=80,∑f
i
u
i
=−26, A= 55 and h= 10
∴
X
=A+h[
N
1
∑f
i
u
i
]
⇒
X
=A+h[
N
1
∑f
i
u
i
]
⇒ =55+10× 80−26 =55−3.25=51.75
Answer:
51
Step-by-step explanation:
The marks in ascending order
25,35,38,45,50,52,54,58,60,80
Median is middle term
If even avg. of middle numbers
Median=50+52/2=51