The marks obtained by 16 students in a class test are: 3, 6, 8, 13, 15, 5, 23, 21,9,10.17
20, 1, 18, 12, 21 Find: (i) the median (ii) lower quartile (iii) upper-quartile
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Answered by
1
Answer:
10, 12, 14, 17, 18, 20, 21 30, 32
N = 9
Median=(
N+1
2
)th itemMedian=(
9+1
2
)th=5th item
Thus, Median is given by the size of the 5th item. Therefore, Median of the data so given is 18.
Answered by
0
Answer:
firstly you have to add the marks of the 16 students that is 3 + 6 + 8 + 13 + 15 + 5 + 21 + 23 + 17 + 10 + 9 + 1 + 21 + 21 + 18 + 12 divided by 2
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