Question

The marks of 20 students in a test is given below: 5,6,8,9,10,11,11,12,13,13,14,14,15,15,15,16,16,18,19,20
Calculate : i) mean ii) median iii) mode​

Answer 1

(i)The mean of the following will be

$\sf\fbox\red{Mean = Sum \: of \: terms \div number \: of \: terms}$

$= 5 + 6 + 8 + 9 + 10 + 11 + 11 + 12 + 13 + 13 + 14 + 14 + 15 + 15 + 15 + 16 + 16 + 18 + 19 + 20 \div$

$= 260 \div 20$

$= 13$

(ii) In the given data there are even numbers so the median will the 10 th and 11 th number addition

$\sf\fbox\red{Median = The \: number \: between \: the \: given \: numbers}$

$= 13 + 14$

$= 27$

(iii) So the most occurring number in the given data is

$\sf\fbox\red{Mode = The \: the \: number \: which \: occurs \: the \: most}$

$=15$

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Answer 2

Answer:

5+6+8+9+10+11+11+12+13+13+14+14+15+15+15+16+16+18+19+20÷

= 260 \div 20=260÷20

= 13=13

(ii) In the given data there are even numbers so the median will the 10 th and 11 th number addition

Median=Thenumberbetweenthegivennumber

= 13 + 14=13+14

= 27=27

(iii) So the most occurring number in the given data is

Mode=Thethenumberwhichoccursthemost

=15=15

Hope it helps ✌

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