Question

the marks of two friends are in the ratio of 3 : 5 .Had both of them scored 10 marks more than ratio would have been 2 : 3 .Find the marks scored by them ?​

Answer 1

A N S W E R :

❍ Let's say, that two friends be x and y, & marks scored by them be 3m and 5m respectively.

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By given CONDITION :

• Both of them scored 10 marks more, than the ratio would have been 2 : 3.

✠ When they scored 10 marks more —

• x's marks = (3m + 10)
• y's marks = (5m + 10)

Therefore,

➟ (3m + 10)/(5m + 10) = 2/3

➟ 3(3m + 10) = 2(5m + 10)

➟ 9m + 30 = 10m + 20

➟ 9m – 10m = 20 – 30

➟ – m = – 10

➟ m = 10 ✰

Hence,

• Marks scored by x, 3m = 3(10) = 30
• Marks scored by y, 5m = 5(10) = 50

∴ Hence, the marks scored by x and y are 30 and 50 respectively$.$

Answer 2

Given :-

The marks of two friends are in the ratio of 3 : 5 .Had both of them scored 10 marks more than ratio would have been 2 : 3

To Find :-

Marks scored

Solution :-

Let the marks scored be 3x and 5x

$\sf\bigg(\dfrac{3x+10}{5x+10}\bigg)=\dfrac{2}{3}$

$\sf 3(3x+10) = 2(5x + 10)$

$\sf 9x + 30= 10x + 20$

$\sf 20-10=10x-9x$

$\sf 10=x$

Marks scored by them

5(10) = 50

3(10) = 30