The mass and diameter of a planet twice that of earth. If the length of the seconds pendulum on earth is 1m. The length of the seconds pendulum on that planet is:
Answers
SOLUTION.
Time period of Second hand on earth Is same as that on the planet.
T(e) = T(p)
We know that the time period of the second hand is 60sec as it complete one revolution in 60sec.
T(e) = 60sec.
T(p) = 60sec.
Mathematically...
time period = 2π√l/g
60 = 2π√1/g......for earth
Where l is the length of hand and g is the gravity on the planet.
Let the length of hand on that planet is L.
60 = 2π√L/g°.......(3)
where g° is the gravity on that planet
M° is the mass of the planet
R° is the radius of the planet
M is the mass of earth
R is the radi of earth
g° = GM°/(R°)²
g° = 2GM/(2R)²
g° = GM/2R²..... (1)
if g is the gravity on earth
g = GM/R².....put in (1)
g° = g/2.....(2)
put (2) in (3)
60 = 2π√2L/g
from equation of time period for earth we get
60 = 2π/√g
60 = 60√2L
√2L = 1
L = 1/2m
#answerwithquality
#BAL
Answer:
L = 1/2
Explanation:
Thanks
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