Question

The mass and radius of a planet is double that of earth.The time period of simple pendulum on planet,if T is the time period of simple pendulum on earth

Answer 1

Answer:

Explanation:

we know, acceleration due to gravity, g = GM/R²

where M is mass of the planet , R is the radius of the planet.

so, g is directly proportional to M and inversely proportional to r².

a/c to question, mass and radius of a planet are doubled that of the earth.

e.g., M' = 2M and , R' = 2R

so, g' = G(2M)/(2R)² = GM/2R² = g/2

hence, acceleration due to gravity of planet is half of acceleration due to gravity of earth.

as time period is inversely proportional to square root of acceleration due to gravity.

so,

Where  denotes time period of pendulum on the earth and denotes the time period of pendulum on the planet.

given,

so, T/ = √{1/2}[/tex]

= √2T

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