Question

The mass and radius of a sphere is given as
(20 + 0.2)gm, r = (2 + 0.2)cm. The
percentange error in its volume is-
m
3.1%
11%
31%
3%
​

Answer 1

Explanation:

the volume is given as

V = (4/3)πr3

so,

V = (4/3) x 3.14 x 5.33

thus,

V = 623.30 cm3

now, the error equation

ΔV/V = 3(Δr/r)

or

ΔV = V x 3(Δr/r)

thus,

ΔV = 623.30 x 3x(0.1/5.3)

or error in surface area

ΔV = +/- 35.28 cm3

thus,

ΔV/V x 100 = (35.28/623.30) x 100

so,

ΔV/V x 100 = 5.66 %