The mass and radius of a sphere is given as
(20 + 0.2)gm, r = (2 0.2)cm. The
percentange error in its volume is-
m
Answers
Answered by
0
Answer:
Answer
We know Sufrace Area of sphere (S)=4πr
2
=4×
7
22
(2.1)
2
=55.44cm
2
And ΔS=8πrΔr=8×
7
22
×2.1×0.5=26.4cm
2
Therefore, The Ans is 55.44±26.4cm
2
Answered by
1
The radius of a sphere is measured to be (2.1±0.5)cm. Calculate its surface area with error limits.
1.7 ×10 power -6 m power 3
1.7 ×10 power -6 m power 3
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