Question

The mass collide in air stick together. After how much time
combined mass will fall to the ground (calculate the time from the
starting when the motion was started)​

Answer 1

Answer:

let m1 and M2 be the mass of two objects

initial momentum of m1 before collision =m1u1

initial momentum of M2 before collision=m2u2

therefore, total initial momentum=m1u1+m2u2

now, after collision the objects combine therefore,total final momentum =(m1+M2)v

now,from momentum conservation law

=) m1u1+m2u2=(m1+M2)v

=)t= v-u/a

therefore time is v-u/a

Answer 2

A lot of air collisions stick together and after a while they will fall to the ground by is:

• The collision when objects are cohesive is sometimes called complete in elastic collisions because it reduces the internal kinetic energy than any other type of in elastic collision.
• In fact, such a collision reduces the amount of internal kinetic energy to a minimum while maintaining momentum.
• Time taken to get down while falling from a very high altitude = v1 / g = 98 / 9.8 seconds = 10 seconds.
• Total time taken up and down movements = 10 seconds + 10 seconds = 20 seconds.
• Speed just before touching the ground = similar to the first throwing speed = 98 m / s.