Question

The mass, m grams of silver deposited on a metallic surface is directly proportional to the number of
hours 't'during which the electric current is being kept steady. The mass deposited is 1.8 grams when
the time is 0.3 hours. Find the number of grams of silver that will be deposited in 2.5 hours​

Answer 1

Answer:

Calculation of mass of Ag deposited : The electrode reaction is Ag+ + e- → Ag The quantity of electricity passed = Current x Time = 0.5 (amp.) x 2 x 60 x 60 (sec) = 3600 C. From the electrode reaction, it is clear that 96500 C of electricity deposit Ag = 108 g Calculation of thickness: Let the thickness of silver deposited be x cm. Mass = Volume x Density = Area x Thickness x Density (Volume = Area x thickness) Read more on Sarthaks.com - https://www.sarthaks.com/197447/silver-is-uniformly-electro-deposited-metallic-vessel-of-surface-area-of-900-cm-by-passing?show=197458#a197458